NOJ[1093] HTML 即HDU1088 对字符串的处理

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NOJ[1093] HTML 即HDU1088 对字符串的处理

来源: 作者: 时间:2016-02-16 10:05
[1093] HTML时间限制: 1000 ms 内存限制: 65535 K问题描述If you ever tried to read a html document on a Macintosh, you know how hard it is if no Netscape is installed.Now,...

[1093] HTML
时间限制: 1000 ms 内存限制: 65535 K
问题描述
If you ever tried to read a document on a Macintosh, you know how hard it is if no Netscape is installed.
Now, who can forget to install a HTML browser? This is very easy because most of the times you don't need one on a MAC because there is a Acrobate Reader which is native to MAC. But if you ever need one, what do you do?
Your task is to write a small html-browser. It should only display the content of the input-file and knows only the html commands (tags) <br> which is a linebreak and <hr> which is a horizontal ruler. Then you should treat all tabulators, spaces and newlines as one space and display the resulting text with no more than 80 characters on a line.
输入
The input consists of a text you should display. This text consists of words and HTML tags separated by one or more spaces, tabulators or newlines.
A word is a sequence of letters, numbers and punctuation. For example, "abc,123" is one word, but "abc, 123" are two words, namely "abc," and "123". A word is always shorter than 81 characters and does not contain any '<' or '>'. All HTML tags are either <br> or <hr>.
输出
You should display the the resulting text using this rules:
If you read a word in the input and the resulting line does not get longer than 80 chars, print it, else print it on a new line.
If you read a <br> in the input, start a new line.
If you read a <hr> in the input, start a new line unless you already are at the beginning of a line, display 80 characters of '-' and start a new line (again).
The last line is ended by a newline character.
样例输入
Hallo, dies ist eine
ziemlich lange Zeile, die in Html
aber nicht umgebrochen wird.
<br>
Zwei <br> <br> produzieren zwei Newlines.
Es gibt auch noch das tag <hr> was einen Trenner darstellt.
Zwei <hr> <hr> produzieren zwei Horizontal Rulers.
Achtung       mehrere Leerzeichen irritieren

Html genauso wenig wie


mehrere Leerzeilen.样例输出
Hallo, dies ist eine ziemlich lange Zeile, die in Html aber nicht umgebrochen
wird.
Zwei

produzieren zwei Newlines. Es gibt auch noch das tag
--------------------------------------------------------------------------------
was einen Trenner darstellt. Zwei
--------------------------------------------------------------------------------
--------------------------------------------------------------------------------
produzieren zwei Horizontal Rulers. Achtung mehrere Leerzeichen irritieren Html
genauso wenig wie mehrere Leerzeilen.
提示
无来源
Ulm Local 1999
 
题意 :  输入1堆字符  每行最多80个   每个单词都是连续的  不连续的不算一个单词 即不给空格 tab 等分开的字符  一个单词中不包含<  >  包含其他符号
 
如果遇到 <br> 则输出空格
遇到<hr>  则换到下一行 然后输出80个-  然后再换一行 注意 如果是已经在一个新的一行了 就不用再换到下一行后再输出80个‘-’ 就可以直接输出
输出的时候 每行最多有80个字符   每个单词之间有1个空格
 
 
[cpp]
#include<stdio.h>  
#include<string.h>  
int main() 

    char str[100]; 
 
    int cnt=0;//数每行的字符数  
    bool first=true;//记录是否是一行的开头   
    while(scanf("%s",&str)!=EOF) 
    { 
        if(strcmp(str,"<br>")==0){printf("\n");cnt=0;first=true;continue;} 
        if(strcmp(str,"<hr>")==0) 
        { 
            if(!first){printf("\n");first=true;} 
            for(int i=0;i<80;i++)printf("-"); 
            printf("\n");first=true;cnt=0; 
            continue; 
        } 
        if(first) 
        { 
            printf("%s",str); 
            cnt+=strlen(str);first=false; 
            continue; 
        } 
        cnt+=(strlen(str)+1);first=false; 
        if(cnt<=80) 
        { 
            printf(" %s",str); 
            continue; 
        } 
        else 
        { 
            printf("\n"); 
            printf("%s",str); 
            cnt=strlen(str);first=false; 
        } 
    } 
    if(!first)printf("\n");//最后以新行结束  
    return 0; 

#include<stdio.h>
#include<string.h>
int main()
{
    char str[100];

    int cnt=0;//数每行的字符数
    bool first=true;//记录是否是一行的开头
    while(scanf("%s",&str)!=EOF)
    {
        if(strcmp(str,"<br>")==0){printf("\n");cnt=0;first=true;continue;}
        if(strcmp(str,"<hr>")==0)
        {
            if(!first){printf("\n");first=true;}
            for(int i=0;i<80;i++)printf("-");
            printf("\n");first=true;cnt=0;
            continue;
        }
        if(first)
        {
            printf("%s",str);
            cnt+=strlen(str);first=false;
            continue;
        }
        cnt+=(strlen(str)+1);first=false;
        if(cnt<=80)
        {
            printf(" %s",str);
            continue;
        }
        else
        {
            printf("\n");
            printf("%s",str);
            cnt=strlen(str);first=false;
        }
    }
    if(!first)printf("\n");//最后以新行结束
    return 0;
}

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