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借用构造函数,借助call或apply,使用SuPErclass构造函数,缺少函数复用
function Superclass(name = 'default') {
this.name = name;
}
function Subclass(age = 22, name) {
this.age = age;
Superclass.call(this, name);
this.say = function () {
console.LOG(`this.name=${this.name}...this.age=${this.age}`);
};
}
const test = new Subclass(23);
test.say();
console.log(`test instanceof Subclass`, test instanceof Subclass);
console.log(`test instanceof Superclass`, test instanceof Superclass);
console.log(test.__PRoto__.constructor);
console.log(Subclass.prototype.constructor);
原型链继承,使用prototype指向Superclass对象,子类无法给父类传递参数,无法使用字面量添加新方法,所有子类对象共享父类所有方法和属性(引用类型)
function Superclass(name = 'default') {
this.name = name;
this.colors = ['r', 'y'];
}
function Subclass(age = 22) {
this.age = age;
this.say = function () {
console.log(`this.name=${this.name}...this.age=${this.age}`);
};
}
Subclass.prototype = new Superclass();
Subclass.prototype.constructor = Subclass;
const test = new Subclass(23);
const test1 = new Subclass(24);
test.colors.push('b');
console.log(test.colors);
console.log(test1.colors);
test.say();
test1.say();
console.log(`test instanceof Subclass`, test instanceof Subclass);
console.log(`test instanceof Superclass`, test instanceof Superclass);
console.log(test.__proto__.constructor);
console.log(Subclass.prototype.constructor);
组合继承,prototype+call/apply,借用构造函数对实例属性继承,prototype对共享方法继承,会调用两次父类构造函数
function Superclass(name = 'default') {
this.name = name;
}
Superclass.prototype.say = function () {
console.log(this.name);
};
function Subclass(age = 22, name) {
this.age = age;
Superclass.call(name);
}
Subclass.prototype = new Superclass();
Subclass.prototype.constructor = Subclass;
const test = new Subclass(23);
test.say();
console.log(`test instanceof Subclass`, test instanceof Subclass);
console.log(`test instanceof Superclass`, test instanceof Superclass);
console.log(test.__proto__.constructor);
console.log(Subclass.prototype.constructor);
ES6 Class继承
class Superclass {
constructor(name = 'default') {
this.name = name;
}
}
class Subclass extends Superclass {
constructor(age = 22, name) {
super(name);
this.age = age;
}
say() {
console.log(`this.name=${this.name}...this.age=${this.age}`);
}
}
const test = new Subclass(23);
test.say();
console.log(`test instanceof Subclass`, test instanceof Subclass);
console.log(`test instanceof Superclass`, test instanceof Superclass);
console.log(test.__proto__.constructor);
console.log(Subclass.prototype.constructor);
function Superclass(name = 'default') {
this.name = name;
}
function Subclass(age = 22, name) {
this.age = 22;
Superclass.call(this, name);
this.say = function () {
console.log(`this.name=${this.name}...this.age=${this.age}`);
};
}
require('util').inherits(Subclass, Superclass);
const test = new Subclass(23);
test.say();
console.log(`test instanceof Subclass`, test instanceof Subclass);
console.log(`test instanceof Superclass`, test instanceof Superclass);
console.log(test.__proto__.constructor);
console.log(Subclass.prototype.constructor);
以上是脚本宝典为你收集整理的Node.js中的继承全部内容,希望文章能够帮你解决Node.js中的继承所遇到的问题。
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