我一直在制作一个综合的社交媒体饲料课程,可以从FaceBook获取帖子,博客和推特上的推文.然后它将它们组合成一个列表以在站点上显示.问题是,很少看到任何一种帖子类型,因为TwITter比其他两种更活跃.

我设法让它始终显示每种类型中的至少一种,但是我通过计算最终数组中每种类型的数量然后将它们拼接到最后(如果没有)并且想知道是否有更优雅来做到这一点解决这个问题？

我的数组包含一堆数组,每个数组都有一个’tyPE’值,这是我需要测试的/至少有一个.

在拼接之前：

Array
(
    [0] => Array
        (
            [id] => 131403235838803968
            [From] => foo
            [sent] => 1320163947
            [type] => tweet
            [htML] => bar
        )

    [1] => Array
        (
            [id] => 131403233250914304
            [from] => foo
            [sent] => 1320163946
            [type] => tweet
            [html] => bar
        )

    [2] => Array
        (
            [id] => 131403232835674113
            [from] => foo
            [sent] => 1320163946
            [type] => tweet
            [html] => bar
        )

    [3] => Array
        (
            [id] => 131403230910480384
            [from] => foo
            [sent] => 1320163946
            [type] => tweet
            [html] => bar
        )

    [4] => Array
        (
            [id] => 131403228834299904
            [from] => foo
            [sent] => 1320163945
            [type] => tweet
            [html] => bar
        )

    [5] => Array
        (
            [type] => facebook
            [from] => foo
            [html] => bar
            [sent] => 1320065996
        )

    [6] => Array
        (
            [type] => facebook
            [from] => foo
            [html] => bar
            [sent] => 1319808945
        )

    [7] => Array
        (
            [type] => facebook
            [from] => foo
            [html] => bar
            [sent] => 1319789640
        )

    [8] => Array
        (
            [type] => facebook
            [from] => foo
            [html] => bar
            [sent] => 1319707799
        )

    [9] => Array
        (
            [type] => facebook
            [from] => foo
            [html] => bar
            [sent] => 1319617295
        )

    [10] => Array
        (
            [type] => blogger
            [from] => foo
            [html] => bar
            [sent] => 1320157500
        )

    [11] => Array
        (
            [type] => bLOGger
            [from] => foo
            [html] => bar
            [sent] => 1320148260
        )

)

之后它将拥有最新的5个.但是我希望它有最新的五个,但要确保它至少有一个类型’blogger’和一个类型’facebook’在最终数组中.

使用Johnny Craig的想法和以下代码完成了它的工作：

$output = array();  
$output[] = $tweets[0];
$output[] = $items[0];
$output[] = $posts[0];
$Feed = array_merge($tweets,$items,$posts);
$i = 0;
while ($limit > count($output)) {
    if (!in_array($Feed[$i],$output)) {
        $output[] = $Feed[$i];
    }
    $i++;
}

但不是很确定我喜欢它