我有一个网页,以表格/表格的形式返回搜索结果.我想有一个全选复选框,可以选择搜索结果的所有复选框.我的显示结果代码如下：

<form action="noJavaScript.PHP" name="theForm" method="post">
<table style="border: 1px solid black" RULES=ALL FRAME=VSIDES>
<th> </th><th>Order #</th><th>InsPEctor</th><th>Reference #</th><th>Client Name</th><th>PRoperty Address</th><th>CITy</th><th>state</th><th>Zip</th><th>inspection Date</th>
        <?PHP
            while ($row = MysqL_fetch_assoc($result))
            {
                echo '<tr><td>';
                echo '<input type="checkBox" name="selected[]" value="'.$row['order_number'].'"/>';
                echo '</td>';
                foreach ($row as $key => $value)
                    echo '<td>'.htMLspecialchars($value).'</td>';
                echo '</tr>';
            }
        ?>

    </table>
<input type="submit" name="submit" value="Edit/Modify Order" onClick="document.theForm.action='modify.PHP'">
<input type="submit" name="submit" value="Clone Order" onClick="document.theForm.action='clone.PHP'">
<input type="submit" name="submit" value="Delete Order" onClick="document.theForm.action='deleteorder.PHP'">
<input type="submit" name="submit" value="Archive Order" onClick="document.theForm.action='archive.PHP'">

</form>

我试过使用以下功能：

<script type="text/javascript"
<!--
function SetAllCheckBoxes(FormName,FieldName,CheckValue)
{
    if(!document.forms[FormName])
        return;
    VAR objCheckBoxes = document.forms[FormName].elements[FieldName];
    if(!objCheckBoxes)
        return;
    var countCheckBoxes = objCheckBoxes.length;
    if(!countCheckBoxes)
        objCheckBoxes.checked = CheckValue;
    else
        // set the check value for all check Boxes
        for(var i = 0; i < countCheckBoxes; i++)
            objCheckBoxes[i].checked = CheckValue;
}
// -->
</script>

这样的按钮：

<input type="button" onclick="SetAllCheckBoxes('theForm','myCheckBox',true);" value="Check All">;

但我无法让它发挥作用.