在下面的代码中,我展示了我编写的用于创建一些测试数据的夹具.为了设置和分配数据之间的众多关系,显然很长.

public function load(ObjectManager $manager)
{
    $videoTyPE = new Mediatype();
    $videoType->setName('video');
    $videoType->setType('video');

    $manager->persist($videoType);

    $speaker1 = new Speaker();
    $speaker1->setName('Joe bloggs');

    $speaker1->setBiography('Joe BLOGgs bio.');

    $manager->persist($speaker1);

    $category1 = new Category();
    $category1->setName('PHP');
    $category1->setSlug('PHP');

    $manager->persist($category1);

    $tag1 = new Tag();
    $tag1->setName('PHPNW');
    $tag1->setSlug('PHPnw');

    $manager->persist($tag1);

    $video1 = new Media();
    $video1->setMediatype($videoType);
    $video1->setSpeakers(
        new ArrayCollection(
            array(
                $speaker1
            )
        )
    );

    $video1->setCategories(
        new ArrayCollection(
            array(
                $category1
            )
        )
    );

    $video1->setTags(
        new ArrayCollection(
            array(
                $tag1
            )
        )
    );

    $video1->setDate(new \Datetime());
    $video1->setCreationDate(new \DateTime());
    $video1->setTITle('My video about PHP');
    $video1->setDescription('A video about PHP!');
    $video1->setContent('http://some.video-url.COM');
    $video1->setLength('20:00:00');
    $video1->setrating(2.5);
    $video1->setVisits(100);
    $video1->setLanguage('EN');
    $video1->setHostName('PHP');
    $video1->setHostUrl('PHP');
    $video1->setstatus('pub');
    $manager->persist($video1);
    $manager->flush();
}

现在我想用真实数据替换这个夹具,并在一个夹具中加载十几个Media实体.我可以复制并粘贴它十几次并更改数据,但这很麻烦,难以维护.有没有一种很好的方法来加载这样的相同类型的众多实体？