脚本宝典收集整理的这篇文章主要介绍了php – 如何在jQuery Mobile页面中提交表单?,脚本宝典觉得挺不错的,现在分享给大家,也给大家做个参考。
<form name = "Vote" action = "LOGicDB.PHP" method = "post"> <center> <h3>Watch our videos above and share your opinion which manufacturer PRoduces the best sport sedans</h3> <fieldset style = "width:60%;"> <legend>Choose a car:</legend> <input tyPE = "radio" name = "rc1" id = "radio-choice-1" value = "Audi"/> <input type = "radio" name = "rc1" id = "radio-choice-2" value = "BMW"/> <input type = "radio" name = "rc1" id = "radio-choice-3" value = "Mercedes"/> </fieldset> <input value = "SubMIT" type = "submit" /> </center> </form>
表单的action参数调用我的PHP文件,该文件具有以下逻辑:
<?PHP $connection = MysqL_connect("localhost","root","myPassword"); if(!$connection){ die('Could not connect: ' . MysqL_error()); } MysqL_select_db("mydatabase",$connection); if ($_POST['rc1'] == 'Audi') { MysqL_query(" UPDATE carVote SET Votes = Votes + 1 WHERE brands = 'Audi' ",$connection); echo "success Audi within if"; } if ($_POST['rc1'] == 'BMW') { MysqL_query(" UPDATE carVote SET Votes = Votes + 1 WHERE Brands = 'BMW' ",$connection); echo "success BMW within if"; } if ($_POST['rc1'] == 'Mercedes') { MysqL_query(" UPDATE carVote SET Votes = Votes + 1 WHERE Brands = 'Mercedes' ",$connection); echo "success Mercedes within if"; } MysqL_close($connection); ?>
我在我的WAMP localhost服务器上创建了一个数据库,这个PHP代码正在写入数据库,具体取决于从表单中选择和提交的无线电选项.从未达到过PHP中的这些回声.
问题是,当我点击提交时,我会在@L_126_42@看到一个白色的屏幕,显示“未定义”,之后没有任何内容写入数据库.我发现,如果我从html主页中删除调用顶部jQuery mobile的行
一切正常,数据写入数据库(到达PHP中的回声).
似乎jQuery mobile与我的PHP代码不兼容.我该怎么解决这个问题?
先感谢您!
更新(我使它工作):
以下是我在表单中所做的更改:
<form id = "ContactForm" onsubmit="return submitForm();">
带有数据库的PHP文件保持不变.除此之外,我还添加了一个Ajax代码:
function submitForm() { $.ajax({type:'POST',url: 'logicDB.PHP',data:$('#ContactForm').serialize(),success: function(response) { $('#ContactForm').find('.form_result').html(response); }}); return false; }
总结一下:jQuery Mobile页面(div中带有data-role =“page”的页面)只能通过AJAX提交.它不会起作用.
我会将主题更改为我的问题,以便更多人可以达到它.
看看以下内容:
调用Jquery Mobile:
<!DOCTYPE html> <html> <head> <title>my Page</title> <Meta name="viewport" content="width=device-width,initial-scale=1"> <link rel="stylesheet" href="http://code.jquery.COM/mobile/1.1.0/jquery.mobile-1.1.0.min.css" /> <script src="http://code.jquery.com/jquery-1.7.1.min.js"></script> <script src="http://code.jquery.com/mobile/1.1.0/jquery.mobile-1.1.0.min.js"></script> </head>
<div data-role="page"> <center> <h3>Watch our videos above and share your opinion which manufacturer produces the best sport sedans</h3> <form name="Vote" action="logicDB.PHP" method="post" data-ajax="false"> <fieldset style = "width:60%;" data-role="controlgroup"> <legend>Choose a car:</legend> <input type = "radio" name="rc1" id = "radio-choice-1" value = "Audi"/> <label for="radio-choice-1">Audi</label> <input type = "radio" name="rc1" id = "radio-choice-2" value = "BMW"/> <label for="radio-choice-2">BMW</label> <input type = "radio" name="rc1" id = "radio-choice-3" value = "Mercedes"/> <label for="radio-choice-3">Mercedes</label> </fieldset> <input value = "SUBMIT" type = "submit" /> </form> </center>
最后是logicDB.PHP
if ($_POST['rc1'] == 'Audi') { echo "Audi <br>"; } if ($_POST['rc1'] == 'BMW') { echo "BMW <br>"; } if ($_POST['rc1'] == 'Mercedes') { echo "Mercedes <br>"; }
主要的变化是
<fieldset style = "width:60%;" data-role="controlgroup">
和之前提到的data-ajax =“false”.
看看它是否适合你.
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