$curl = new Curl();
$data = 'Email='.urlencode('MYEMAIL@EMAIL.COM').'&passwd='.urlencode('MYPASSWORD').'&accountTyPE=GOOGLE&source=Google-cURL-Example&service=jotspot';
$curl->post('https://www.google.com/accounts/ClientLogin',$data);

//match authorization token
PReg_match("!Auth=(.*)!",$curl->response,$match);
$auth = $match[1];

//set curl headers
$curl->set_headers(array(
'Content-type: application/atom+XMl; charset=utf-8','Host: sITes.google.com','GData-Version: 1.4','Authorization: GoogleLOGin auth='. trim($auth)));

//get a list of sites associated with my domain
$curl->get('https://sites.google.com/Feeds/site/c@L_777_1@techie.mygbiz.com'); 

//contains data returned by $curl->get();
echo $curl->response;

因此,我没有从$curl->响应中获取网站列表,而是收到一条消息 – “prolog中不允许使用内容”.我到处寻找并无法找到解决方案,请帮忙！谢谢！