我有一个 mysql表,有一些奇怪的id是这样的：

╔═══╦════════════╦═════════════╦═══════════╦═════════════╦═══════════╗
║   ║     id     ║   user_id   ║  hours_a  ║   hours_b   ║  hours_c  ║
╠═══╬════════════╬═════════════╬═══════════╬═════════════╬═══════════╣
║ 1 ║ 010120149  ║     9       ║    10     ║     6       ║    23     ║
║ 2 ║ 0212201310 ║     10      ║    2      ║     8       ║    10     ║
║ 3 ║ 021220138  ║     8       ║    1      ║     4       ║     9     ║
║ 4 ║ 020120149  ║     9       ║    3      ║     8       ║    10     ║
╚═══╩════════════╩═════════════╩═══════════╩═════════════╩═══════════╝

我正在尝试解析用户ID 9的总小时数,对于2014年1月和2014年.从表中可以看出,这是第一行和最后一行.

例如,01 01 2014 9是第一行的ID,表示DD / MM / yyYY / ID.

我希望能够为user_id = 9检索所有小时数(hours_a,hours_b& hours_c),其中day = 01 – 31(循环所有日期？),month = 01和year = 2014.

要以这样的方式导出：

{"userid":"9","month":"01","year":"2014","total_hours_a":"13","total_hours_b":"14","total_hours_c":"33"}

ID代表Day,Month,Year和Userid,如下所示：

目前我在做什么

目前我正在选择所有表格：

$query="SELECT * From `weird_table` WHERE `id` LIKE 9";

将其打印到编码的json：

$result = MysqL_query($query);
$temp = 0;
$JSON = array();

while ($row = MysqL_fetch_array($result))
    {
    $json[$temp]['id'] = $row['id'];
    $json[$temp]['userid'] = $row['userid'];
    $json[$temp]['hours_a'] = $row['hours_a'];
    $json[$temp]['hours_b'] = $row['hours_b'];
    $json[$temp]['hours_c'] = $row['hours_c'];
    }

$temp++;
}

PRint json_encode($json);
MysqL_close();

然后客户端(因为我是前端开发人员),我混合和匹配&总结并得到我想要的结果.而不是做所有这些麻烦,给用户这么多的cpu痛苦;我希望服务器完成工作并打印我正在寻找的东西.

SELECT *,(hours_a + hours_b + hours_c) totalHours
From weird_table 
WHERE user_id = 9 AND 
      STR_TO_DATE(SubSTRING(id,1,8),'%d%m%Y') BETWEEN '2014-01-01' AND '2014-01-31'

SELECT *,(hours_a + hours_b + hours_c) totalHours 
FROM weird_table 
WHERE user_id = 9 AND SUBSTRING(id,3,6) = '012014'

SELECT *,(hours_a + hours_b + hours_c) totalHours
FROM weird_table 
WHERE user_id = 9 AND 
      YEAR(STR_TO_DATE(SUBSTRING(id,'%d%m%Y')) = 2014 AND 
      MONTH(STR_TO_DATE(SUBSTRING(id,'%d%m%Y')) = 1