我有一个名为ForgotPasswordPage.PHP的自定义页面和一个ForgotPasswordPage.ss模板.我还在ForgotPassworDForm.PHP中有一个自定义Form类,它在templates / Includes目录中有相应的自定义Form模板ForgotPasswordForm.ss.
表单操作应该调用doForgotPassword,但是从不调用此函数,否则,我将被发送到GOOGLE.COM.
这似乎是如此基本,但我有两个开发人员在看它,我们得到的是以下错误：

似乎存在技术问题.请单击后退按钮,刷新浏览器,然后重试.

我在这做错了什么？

ForgotPasswordForm.PHP

<?PHP

class ForgotPasswordForm extends Form { 
    function __construct($controller,$name,$arguments=array()) { 
        $fields = new FieldList( 
            EmailField::create("Email") 
        ); 
        $actions = new FieldList(FormAction::create("doForgotPassword")->setTITle("RETRIEVE PASSWORD")); 
        $validator = new requiredFields('Email'); 
        parent::__construct($controller,$fields,$actions,$validator); 
    }

    public function doForgotPassword($data,Form $form) { 
        //As a test,if we ever get here,the controller should send me to the Google website
        Controller::curr()->redirect('http://www.google.com'); 
    }

    public function forTemplate() { 
        return $this->renderWith(array( 
            $this->class,'Form' 
        )); 
    }

}

ForgotPasswordForm.ss

<form $FormAttributes> 
    <label for="{$FormName}_Email">Enter Your Email Address</label> 
    $Fields.datafieldByName(Email) 
    <% if $Actions %> 
        <% loop $Actions %> 
            $Field 
        <% end_loop %> 
    <% end_if %> 
</form>

ForgotPasswordPage.PHP

class ForgotPasswordPage extends Page { 
. 
. 
. 
}

class ForgotPasswordPage_Controller extends Page_Controller {

    public static $Allowed_actions = array ( 
        'MyForgotPasswordForm' 
    );

    public function init() { 
        parent::init(); 
    }

    public function MyForgotPasswordForm(){ 
        return new ForgotPasswordForm($this,'MyForgotPasswordForm'); 
    }

}

ForgotPasswordPage.ss

. 
. 
. 
$MyForgotPasswordForm 
. 
. 
.