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我知道您可以使用foreach(或for循环)检索键/值对,如下所示.
$stockPRices= array("GOOGLE"=>"800","Apple"=>"400","Microsoft"=>"4","RIM"=>"15","FaceBook"=>"30"); foreach ($stockprices as $key =>$price)
$states=(array([0]=>array("capITal"=> "Sacramento","joined_union"=>1850,"population_rank"=> 1),[1]=>array("capital"=> "Austin","joined_union"=>1845,"population_rank"=> 2),[2]=>array("capital"=> "Boston","joined_union"=>1788,"population_rank"=> 14) ));
我的第一个问题非常基本：我知道“大写”,“joined_union”,“population_rank”是关键,“萨克拉门托”,“1850”,“1”是值(正确吗？).但你怎么称呼[0] [1] [2]？它们是“主键”和“大写”等子键吗？我找不到任何定义;无论是在书中还是在线.
主要问题是如何检索数组[0] [1] [2]？假设我想在1845年获得join_union的数组(或者在19世纪更加棘手),然后删除该数组.
最后,我可以将Arrays [0] [1] [2]命名为加利福尼亚州,德克萨斯州和马萨诸塞州吗？
$states=(array("California"=>array("capital"=> "Sacramento","Texas"=>array("capital"=> "Austin","Massachusetts"=>array("capital"=> "Boston","population_rank"=> 14)
));
$states = array(
"California" => array(
"capital" => "Sacramento","joined_union" => 1850,"population_rank" => 1
),"Texas" => array(
"capital" => "Austin","joined_union" => 1845,"population_rank" => 2
),"Massachusetts" => array(
"capital" => "Boston","joined_union" => 1788,"population_rank" => 14
)
);
$joined1850_loop = array();
foreach( $states as $stateName => $stateData ) {
if( $stateData['joined_union'] == 1850 ) {
$joined1850_loop[$stateName] = $stateData;
}
}
print_r( $joined1850_loop );
/*
Array
(
[California] => Array
(
[capital] => Sacramento
[joined_union] => 1850
[population_rank] => 1
)
)
*/
2)使用array_filter功能：
$joined1850 = array_filter(
$states,function( $state ) {
return $state['joined_union'] == 1850;
}
);
print_r( $joined1850 );
/*
Array
(
[California] => Array
(
[capital] => Sacramento
[joined_union] => 1850
[population_rank] => 1
)
)
*/
–
$joined1800s = array_filter(
$states,function ( $state ){
return $state['joined_union'] >= 1800 && $state['joined_union'] < 1900;
}
);
print_r( $joined1800s );
/*
Array
(
[California] => Array
(
[capital] => Sacramento
[joined_union] => 1850
[population_rank] => 1
)
[Texas] => Array
(
[capital] => Austin
[joined_union] => 1845
[population_rank] => 2
)
)
*/
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